Base | Representation |
---|---|
bin | 101111100111101110… |
… | …111100110110010011 |
3 | 11212222111210101000011 |
4 | 233213232330312103 |
5 | 1314204404010021 |
6 | 35253454335351 |
7 | 3460052644216 |
oct | 574756746623 |
9 | 155874711004 |
10 | 51132485011 |
11 | 1a759a55883 |
12 | 9ab01ba557 |
13 | 4a8b5857ba |
14 | 2690cc777d |
15 | 14e3ee5de1 |
hex | be7bbcd93 |
51132485011 has 8 divisors (see below), whose sum is σ = 52262280000. Its totient is φ = 50004434688.
The previous prime is 51132484957. The next prime is 51132485081. The reversal of 51132485011 is 11058423115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51132485011 - 27 = 51132484883 is a prime.
It is a super-2 number, since 2×511324850112 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51132485081) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 376816 + ... + 494221.
It is an arithmetic number, because the mean of its divisors is an integer number (6532785000).
Almost surely, 251132485011 is an apocalyptic number.
51132485011 is a deficient number, since it is larger than the sum of its proper divisors (1129794989).
51132485011 is a wasteful number, since it uses less digits than its factorization.
51132485011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 872333.
The product of its (nonzero) digits is 4800, while the sum is 31.
The spelling of 51132485011 in words is "fifty-one billion, one hundred thirty-two million, four hundred eighty-five thousand, eleven".
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