Base | Representation |
---|---|
bin | 100101001101000100110… |
… | …1000010010111011011011 |
3 | 200002211101001220212212101 |
4 | 1022122021220102323123 |
5 | 1132234034422432443 |
6 | 14513005444024231 |
7 | 1035265560631561 |
oct | 112321150227333 |
9 | 20084331825771 |
10 | 5113320124123 |
11 | 16a16019a7002 |
12 | 6a6bb4692077 |
13 | 2b125139b253 |
14 | 1396b38a3a31 |
15 | 8d02104484d |
hex | 4a689a12edb |
5113320124123 has 4 divisors (see below), whose sum is σ = 5209797862368. Its totient is φ = 5016842385880.
The previous prime is 5113320124111. The next prime is 5113320124147. The reversal of 5113320124123 is 3214210233115.
5113320124123 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5113320124123 is a prime.
It is a super-2 number, since 2×51133201241232 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5113320124091 and 5113320124100.
It is not an unprimeable number, because it can be changed into a prime (5113320124103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48238869043 + ... + 48238869148.
It is an arithmetic number, because the mean of its divisors is an integer number (1302449465592).
Almost surely, 25113320124123 is an apocalyptic number.
5113320124123 is a gapful number since it is divisible by the number (53) formed by its first and last digit.
5113320124123 is a deficient number, since it is larger than the sum of its proper divisors (96477738245).
5113320124123 is an equidigital number, since it uses as much as digits as its factorization.
5113320124123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 96477738244.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 5113320124123 its reverse (3214210233115), we get a palindrome (8327530357238).
The spelling of 5113320124123 in words is "five trillion, one hundred thirteen billion, three hundred twenty million, one hundred twenty-four thousand, one hundred twenty-three".
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