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5113320305541 = 37243491443121
BaseRepresentation
bin100101001101000100110…
…1000111111001110000101
3200002211101002021002201120
41022122021220333032011
51132234034444234131
614513005451544153
71035265562315520
oct112321150771605
920084332232646
105113320305541
1116a1602010338
126a6bb475b059
132b12514329b6
141396b390dbb7
158d02107d496
hex4a689a3f385

5113320305541 has 8 divisors (see below), whose sum is σ = 7791726179904. Its totient is φ = 2921897317440.

The previous prime is 5113320305537. The next prime is 5113320305543. The reversal of 5113320305541 is 1455030233115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5113320305541 - 22 = 5113320305537 is a prime.

It is a super-2 number, since 2×51133203055412 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5113320305543) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 121745721540 + ... + 121745721581.

It is an arithmetic number, because the mean of its divisors is an integer number (973965772488).

Almost surely, 25113320305541 is an apocalyptic number.

It is an amenable number.

5113320305541 is a deficient number, since it is larger than the sum of its proper divisors (2678405874363).

5113320305541 is a wasteful number, since it uses less digits than its factorization.

5113320305541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 243491443131.

The product of its (nonzero) digits is 27000, while the sum is 33.

Adding to 5113320305541 its reverse (1455030233115), we get a palindrome (6568350538656).

The spelling of 5113320305541 in words is "five trillion, one hundred thirteen billion, three hundred twenty million, three hundred five thousand, five hundred forty-one".

Divisors: 1 3 7 21 243491443121 730474329363 1704440101847 5113320305541