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51134004313 = 7431491140137
BaseRepresentation
bin101111100111110100…
…101111110001011001
311212222121122120002121
4233213310233301121
51314210301114223
635253551101241
73460101602530
oct574764576131
9155877576077
1051134004313
111a75a8a32a7
129ab0811821
134a8b9981b2
1426911a1317
1514e41e615d
hexbe7d2fc59

51134004313 has 16 divisors (see below), whose sum is σ = 60199286400. Its totient is φ = 42522512256.

The previous prime is 51134004307. The next prime is 51134004331. The reversal of 51134004313 is 31340043115.

It is not a de Polignac number, because 51134004313 - 25 = 51134004281 is a prime.

It is a super-2 number, since 2×511340043132 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51134004343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 525220 + ... + 614917.

It is an arithmetic number, because the mean of its divisors is an integer number (3762455400).

Almost surely, 251134004313 is an apocalyptic number.

It is an amenable number.

51134004313 is a deficient number, since it is larger than the sum of its proper divisors (9065282087).

51134004313 is a wasteful number, since it uses less digits than its factorization.

51134004313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1140336.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 51134004313 its reverse (31340043115), we get a palindrome (82474047428).

The spelling of 51134004313 in words is "fifty-one billion, one hundred thirty-four million, four thousand, three hundred thirteen".

Divisors: 1 7 43 149 301 1043 6407 44849 1140137 7980959 49025891 169880413 343181237 1189162891 7304857759 51134004313