51134110340040 has 320 divisors, whose sum is σ = 211529141429760. Its totient is φ = 10788735306240.

The previous prime is 51134110340029. The next prime is 51134110340063. The reversal of 51134110340040 is 4004301143115.

51134110340040 is a `hidden beast` number, since 5 + 113 + 4 + 1 + 103 + 400 + 40 = 666.

51134110340040 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×51134110340040² (a number of 28 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 51134110339986 and 51134110340013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 86420176 + ... + 87009855.

It is an arithmetic number, because the mean of its divisors is an integer number (661028566968).

Almost surely, 2^{51134110340040} is an apocalyptic number.

It is an amenable number.

51134110340040 is an abundant number, since it is smaller than the sum of its proper divisors (160395031089720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

51134110340040 is a wasteful number, since it uses less digits than its factorization.

51134110340040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 173430074 (or 173430061 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 51134110340040 its reverse (4004301143115), we get a palindrome (55138411483155).

The spelling of 51134110340040 in words is "fifty-one trillion, one hundred thirty-four billion, one hundred ten million, three hundred forty thousand, forty".