Base | Representation |
---|---|
bin | 100101001101001000011… |
… | …0010001010001110000101 |
3 | 200002211200102202211222020 |
4 | 1022122100302022032011 |
5 | 1132234311134303110 |
6 | 14513025412353353 |
7 | 1035301546062456 |
oct | 112322062121605 |
9 | 20084612684866 |
10 | 5113440150405 |
11 | 16a1663726584 |
12 | 6a7028915859 |
13 | 2b1270204112 |
14 | 1396c57c912d |
15 | 8d02b852d70 |
hex | 4a690c8a385 |
5113440150405 has 16 divisors (see below), whose sum is σ = 8183284099584. Its totient is φ = 2726574793920.
The previous prime is 5113440150397. The next prime is 5113440150407. The reversal of 5113440150405 is 5040510443115.
It is not a de Polignac number, because 5113440150405 - 23 = 5113440150397 is a prime.
It is a super-2 number, since 2×51134401504052 (a number of 26 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5113440150407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37009141 + ... + 37147050.
It is an arithmetic number, because the mean of its divisors is an integer number (511455256224).
Almost surely, 25113440150405 is an apocalyptic number.
It is an amenable number.
5113440150405 is a deficient number, since it is larger than the sum of its proper divisors (3069843949179).
5113440150405 is a wasteful number, since it uses less digits than its factorization.
5113440150405 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74160796.
The product of its (nonzero) digits is 24000, while the sum is 33.
The spelling of 5113440150405 in words is "five trillion, one hundred thirteen billion, four hundred forty million, one hundred fifty thousand, four hundred five".
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