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5113510340314 = 22556755170157
BaseRepresentation
bin100101001101001010011…
…1101111010011011011010
3200002211212022211212102111
41022122110331322123122
51132234432121342224
614513040401022534
71035303360506665
oct112322475723332
920084768755374
105113510340314
1116a169a307272
126a7048324a4a
132b128190b1cc
141396d0c5a6dc
158d032ab9d94
hex4a694f7a6da

5113510340314 has 4 divisors (see below), whose sum is σ = 7670265510474. Its totient is φ = 2556755170156.

The previous prime is 5113510340273. The next prime is 5113510340369. The reversal of 5113510340314 is 4130430153115.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 3159623566089 + 1953886774225 = 1777533^2 + 1397815^2 .

It is a super-2 number, since 2×51135103403142 (a number of 26 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1278377585077 + ... + 1278377585080.

Almost surely, 25113510340314 is an apocalyptic number.

5113510340314 is a deficient number, since it is larger than the sum of its proper divisors (2556755170160).

5113510340314 is a wasteful number, since it uses less digits than its factorization.

5113510340314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2556755170159.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 5113510340314 its reverse (4130430153115), we get a palindrome (9243940493429).

The spelling of 5113510340314 in words is "five trillion, one hundred thirteen billion, five hundred ten million, three hundred forty thousand, three hundred fourteen".

Divisors: 1 2 2556755170157 5113510340314