511400343 has 4 divisors (see below), whose sum is σ = 681867128. Its totient is φ = 340933560.

The previous prime is 511400317. The next prime is 511400353. The reversal of 511400343 is 343004115.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 511400343 - 2⁵ = 511400311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (511400353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85233388 + ... + 85233393.

It is an arithmetic number, because the mean of its divisors is an integer number (170466782).

Almost surely, 2^511400343 is an apocalyptic number.

511400343 is a deficient number, since it is larger than the sum of its proper divisors (170466785).

511400343 is a wasteful number, since it uses less digits than its factorization.

511400343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 170466784.

The product of its (nonzero) digits is 720, while the sum is 21.

The square root of 511400343 is about 22614.1624430356. The cubic root of 511400343 is about 799.6875566356.

Adding to 511400343 its reverse (343004115), we get a palindrome (854404458).

The spelling of 511400343 in words is "five hundred eleven million, four hundred thousand, three hundred forty-three".