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51140203151 = 116471439081
BaseRepresentation
bin101111101000001100…
…011001001010001111
311220000001022111022012
4233220030121022033
51314213343000101
635254332011435
73460205361122
oct575014311217
9156001274265
1051140203151
111a763347604
129ab2900b7b
134a9005884b
142691d363b9
1514e4a1cbbb
hexbe831928f

51140203151 has 4 divisors (see below), whose sum is σ = 51140758704. Its totient is φ = 51139647600.

The previous prime is 51140203117. The next prime is 51140203157. The reversal of 51140203151 is 15130204115.

51140203151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51140203151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51140203157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 103070 + ... + 336011.

It is an arithmetic number, because the mean of its divisors is an integer number (12785189676).

Almost surely, 251140203151 is an apocalyptic number.

51140203151 is a deficient number, since it is larger than the sum of its proper divisors (555553).

51140203151 is a wasteful number, since it uses less digits than its factorization.

51140203151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 555552.

The product of its (nonzero) digits is 600, while the sum is 23.

Adding to 51140203151 its reverse (15130204115), we get a palindrome (66270407266).

The spelling of 51140203151 in words is "fifty-one billion, one hundred forty million, two hundred three thousand, one hundred fifty-one".

Divisors: 1 116471 439081 51140203151