Base | Representation |
---|---|
bin | 101111101000001100… |
… | …011001001010001111 |
3 | 11220000001022111022012 |
4 | 233220030121022033 |
5 | 1314213343000101 |
6 | 35254332011435 |
7 | 3460205361122 |
oct | 575014311217 |
9 | 156001274265 |
10 | 51140203151 |
11 | 1a763347604 |
12 | 9ab2900b7b |
13 | 4a9005884b |
14 | 2691d363b9 |
15 | 14e4a1cbbb |
hex | be831928f |
51140203151 has 4 divisors (see below), whose sum is σ = 51140758704. Its totient is φ = 51139647600.
The previous prime is 51140203117. The next prime is 51140203157. The reversal of 51140203151 is 15130204115.
51140203151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51140203151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51140203157) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 103070 + ... + 336011.
It is an arithmetic number, because the mean of its divisors is an integer number (12785189676).
Almost surely, 251140203151 is an apocalyptic number.
51140203151 is a deficient number, since it is larger than the sum of its proper divisors (555553).
51140203151 is a wasteful number, since it uses less digits than its factorization.
51140203151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 555552.
The product of its (nonzero) digits is 600, while the sum is 23.
Adding to 51140203151 its reverse (15130204115), we get a palindrome (66270407266).
The spelling of 51140203151 in words is "fifty-one billion, one hundred forty million, two hundred three thousand, one hundred fifty-one".
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