5114103352653 has 4 divisors (see below), whose sum is σ = 6818804470208. Its totient is φ = 3409402235100.

The previous prime is 5114103352651. The next prime is 5114103352723. The reversal of 5114103352653 is 3562533014115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 5114103352653 - 2¹ = 5114103352651 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5114103352651) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 852350558773 + ... + 852350558778.

It is an arithmetic number, because the mean of its divisors is an integer number (1704701117552).

Almost surely, 2^{5114103352653} is an apocalyptic number.

It is an amenable number.

5114103352653 is a deficient number, since it is larger than the sum of its proper divisors (1704701117555).

5114103352653 is a wasteful number, since it uses less digits than its factorization.

5114103352653 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1704701117554.

The product of its (nonzero) digits is 162000, while the sum is 39.

Adding to 5114103352653 its reverse (3562533014115), we get a palindrome (8676636366768).

The spelling of 5114103352653 in words is "five trillion, one hundred fourteen billion, one hundred three million, three hundred fifty-two thousand, six hundred fifty-three".