Base | Representation |
---|---|
bin | 100101001101011111011… |
… | …0000000001010100100001 |
3 | 200002220200011220102102010 |
4 | 1022122332300001110201 |
5 | 1132242401100412401 |
6 | 14513234121543133 |
7 | 1035326632101345 |
oct | 112327660012441 |
9 | 20086604812363 |
10 | 5114211341601 |
11 | 16a1a19a7a97a |
12 | 6a7203044aa9 |
13 | 2b1363c0b27b |
14 | 139759db5625 |
15 | 8d0743d8ed6 |
hex | 4a6bec01521 |
5114211341601 has 8 divisors (see below), whose sum is σ = 7177840479520. Its totient is φ = 3230028215712.
The previous prime is 5114211341593. The next prime is 5114211341623. The reversal of 5114211341601 is 1061431124115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5114211341601 - 23 = 5114211341593 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5114211341201) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44861502940 + ... + 44861503053.
It is an arithmetic number, because the mean of its divisors is an integer number (897230059940).
Almost surely, 25114211341601 is an apocalyptic number.
It is an amenable number.
5114211341601 is a deficient number, since it is larger than the sum of its proper divisors (2063629137919).
5114211341601 is a wasteful number, since it uses less digits than its factorization.
5114211341601 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89723006015.
The product of its (nonzero) digits is 2880, while the sum is 30.
Adding to 5114211341601 its reverse (1061431124115), we get a palindrome (6175642465716).
The spelling of 5114211341601 in words is "five trillion, one hundred fourteen billion, two hundred eleven million, three hundred forty-one thousand, six hundred one".
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