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5114211341601 = 31989723005993
BaseRepresentation
bin100101001101011111011…
…0000000001010100100001
3200002220200011220102102010
41022122332300001110201
51132242401100412401
614513234121543133
71035326632101345
oct112327660012441
920086604812363
105114211341601
1116a1a19a7a97a
126a7203044aa9
132b1363c0b27b
14139759db5625
158d0743d8ed6
hex4a6bec01521

5114211341601 has 8 divisors (see below), whose sum is σ = 7177840479520. Its totient is φ = 3230028215712.

The previous prime is 5114211341593. The next prime is 5114211341623. The reversal of 5114211341601 is 1061431124115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5114211341601 - 23 = 5114211341593 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5114211341201) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44861502940 + ... + 44861503053.

It is an arithmetic number, because the mean of its divisors is an integer number (897230059940).

Almost surely, 25114211341601 is an apocalyptic number.

It is an amenable number.

5114211341601 is a deficient number, since it is larger than the sum of its proper divisors (2063629137919).

5114211341601 is a wasteful number, since it uses less digits than its factorization.

5114211341601 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 89723006015.

The product of its (nonzero) digits is 2880, while the sum is 30.

Adding to 5114211341601 its reverse (1061431124115), we get a palindrome (6175642465716).

The spelling of 5114211341601 in words is "five trillion, one hundred fourteen billion, two hundred eleven million, three hundred forty-one thousand, six hundred one".

Divisors: 1 3 19 57 89723005993 269169017979 1704737113867 5114211341601