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51142121031 = 3128313287119
BaseRepresentation
bin101111101000010011…
…101101011001000111
311220000011220221010210
4233220103231121013
51314214340333111
635254441050503
73460230566451
oct575023553107
9156004827123
1051142121031
111a764437531
129ab3486a33
134a9057a7a1
1426922b52d1
1514e4c9b0a6
hexbe84ed647

51142121031 has 8 divisors (see below), whose sum is σ = 68242648320. Its totient is φ = 34068170552.

The previous prime is 51142121029. The next prime is 51142121057. The reversal of 51142121031 is 13012124115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 51142121031 - 21 = 51142121029 is a prime.

It is a super-2 number, since 2×511421210312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51142120989 and 51142121007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51142121231) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6639711 + ... + 6647408.

It is an arithmetic number, because the mean of its divisors is an integer number (8530331040).

Almost surely, 251142121031 is an apocalyptic number.

51142121031 is a deficient number, since it is larger than the sum of its proper divisors (17100527289).

51142121031 is a wasteful number, since it uses less digits than its factorization.

51142121031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13288405.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 51142121031 its reverse (13012124115), we get a palindrome (64154245146).

The spelling of 51142121031 in words is "fifty-one billion, one hundred forty-two million, one hundred twenty-one thousand, thirty-one".

Divisors: 1 3 1283 3849 13287119 39861357 17047373677 51142121031