Base | Representation |
---|---|
bin | 101111101000010100… |
… | …000011111011011101 |
3 | 11220000012002121202200 |
4 | 233220110003323131 |
5 | 1314214401311331 |
6 | 35254443042113 |
7 | 3460231432542 |
oct | 575024037335 |
9 | 156005077680 |
10 | 51142213341 |
11 | 1a76449a91a |
12 | 9ab3510339 |
13 | 4a905b07cb |
14 | 26922dabc9 |
15 | 14e4cb85e6 |
hex | be8503edd |
51142213341 has 18 divisors (see below), whose sum is σ = 77964727230. Its totient is φ = 32300343216.
The previous prime is 51142213307. The next prime is 51142213373. The reversal of 51142213341 is 14331224115.
It can be written as a sum of positive squares in only one way, i.e., 28274422500 + 22867790841 = 168150^2 + 151221^2 .
It is not a de Polignac number, because 51142213341 - 217 = 51142082269 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51142213301) by changing a digit.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 7867206 + ... + 7873703.
It is an arithmetic number, because the mean of its divisors is an integer number (4331373735).
Almost surely, 251142213341 is an apocalyptic number.
It is an amenable number.
51142213341 is a deficient number, since it is larger than the sum of its proper divisors (26822513889).
51142213341 is a wasteful number, since it uses less digits than its factorization.
51142213341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15740953 (or 15740931 counting only the distinct ones).
The product of its digits is 2880, while the sum is 27.
Adding to 51142213341 its reverse (14331224115), we get a palindrome (65473437456).
The spelling of 51142213341 in words is "fifty-one billion, one hundred forty-two million, two hundred thirteen thousand, three hundred forty-one".
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