5114234113 has 4 divisors (see below), whose sum is σ = 5116187988. Its totient is φ = 5112280240.

The previous prime is 5114234039. The next prime is 5114234137. The reversal of 5114234113 is 3114324115.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3001177089 + 2113057024 = 54783^2 + 45968^2 .

It is a cyclic number.

It is not a de Polignac number, because 5114234113 - 2²¹ = 5112136961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5114234143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 973006 + ... + 978247.

It is an arithmetic number, because the mean of its divisors is an integer number (1279046997).

Almost surely, 2^5114234113 is an apocalyptic number.

It is an amenable number.

5114234113 is a deficient number, since it is larger than the sum of its proper divisors (1953875).

5114234113 is a wasteful number, since it uses less digits than its factorization.

5114234113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1953874.

The product of its digits is 1440, while the sum is 25.

The square root of 5114234113 is about 71513.8735700983. The cubic root of 5114234113 is about 1722.9005180157.

Adding to 5114234113 its reverse (3114324115), we get a palindrome (8228558228).

The spelling of 5114234113 in words is "five billion, one hundred fourteen million, two hundred thirty-four thousand, one hundred thirteen".