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5114301 = 36127947
BaseRepresentation
bin10011100000100110111101
3100121211111120
4103200212331
52302124201
6301341153
761320333
oct23404675
910554446
105114301
1129834a5
1218677b9
1310a0b1a
14971b53
156b0536
hex4e09bd

5114301 has 8 divisors (see below), whose sum is σ = 6931104. Its totient is φ = 3353520.

The previous prime is 5114293. The next prime is 5114309. The reversal of 5114301 is 1034115.

5114301 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (5114293) and next prime (5114309).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5114301 - 23 = 5114293 is a prime.

5114301 is a lucky number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5114309) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13791 + ... + 14156.

It is an arithmetic number, because the mean of its divisors is an integer number (866388).

Almost surely, 25114301 is an apocalyptic number.

It is an amenable number.

5114301 is a deficient number, since it is larger than the sum of its proper divisors (1816803).

5114301 is a wasteful number, since it uses less digits than its factorization.

5114301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28011.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 5114301 is about 2261.4820361878. The cubic root of 5114301 is about 172.2908029023.

Adding to 5114301 its reverse (1034115), we get a palindrome (6148416).

The spelling of 5114301 in words is "five million, one hundred fourteen thousand, three hundred one".

Divisors: 1 3 61 183 27947 83841 1704767 5114301