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5114313053 = 43451117703
BaseRepresentation
bin1001100001101011…
…00011100101011101
3111012102111000120222
410300311203211131
540433231004203
62203253251125
7240510641453
oct46065434535
914172430528
105114313053
112194995103
12ba8933aa5
13636744155
1436733a9d3
151eded7038
hex130d6395d

5114313053 has 4 divisors (see below), whose sum is σ = 5114474208. Its totient is φ = 5114151900.

The previous prime is 5114313047. The next prime is 5114313089. The reversal of 5114313053 is 3503134115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5114313053 - 210 = 5114312029 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5114313653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15401 + ... + 102302.

It is an arithmetic number, because the mean of its divisors is an integer number (1278618552).

Almost surely, 25114313053 is an apocalyptic number.

It is an amenable number.

5114313053 is a deficient number, since it is larger than the sum of its proper divisors (161155).

5114313053 is a wasteful number, since it uses less digits than its factorization.

5114313053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 161154.

The product of its (nonzero) digits is 2700, while the sum is 26.

The square root of 5114313053 is about 71514.4254888481. The cubic root of 5114313053 is about 1722.9093824950.

Adding to 5114313053 its reverse (3503134115), we get a palindrome (8617447168).

The spelling of 5114313053 in words is "five billion, one hundred fourteen million, three hundred thirteen thousand, fifty-three".

Divisors: 1 43451 117703 5114313053