51143140003 has 4 divisors (see below), whose sum is σ = 51167369088. Its totient is φ = 51118910920.

The previous prime is 51143139973. The next prime is 51143140039. The reversal of 51143140003 is 30004134115.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30004134115 = 5 ⋅6000826823.

It is a cyclic number.

It is not a de Polignac number, because 51143140003 - 2¹³ = 51143131811 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51143140063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12111376 + ... + 12115597.

It is an arithmetic number, because the mean of its divisors is an integer number (12791842272).

Almost surely, 2^51143140003 is an apocalyptic number.

51143140003 is a deficient number, since it is larger than the sum of its proper divisors (24229085).

51143140003 is a wasteful number, since it uses less digits than its factorization.

51143140003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24229084.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 51143140003 its reverse (30004134115), we get a palindrome (81147274118).

The spelling of 51143140003 in words is "fifty-one billion, one hundred forty-three million, one hundred forty thousand, three".