30004134115 has 4 divisors (see below), whose sum is σ = 36004960944. Its totient is φ = 24003307288.

The previous prime is 30004134103. The next prime is 30004134137. The reversal of 30004134115 is 51143140003.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 51143140003 = 2111 ⋅24226973.

It is a cyclic number.

It is not a de Polignac number, because 30004134115 - 2³³ = 21414199523 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3000413407 + ... + 3000413416.

It is an arithmetic number, because the mean of its divisors is an integer number (9001240236).

Almost surely, 2^30004134115 is an apocalyptic number.

30004134115 is a deficient number, since it is larger than the sum of its proper divisors (6000826829).

30004134115 is an equidigital number, since it uses as much as digits as its factorization.

30004134115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6000826828.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 30004134115 its reverse (51143140003), we get a palindrome (81147274118).

The spelling of 30004134115 in words is "thirty billion, four million, one hundred thirty-four thousand, one hundred fifteen".