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5114315341 = 10349653547
BaseRepresentation
bin1001100001101011…
…00100001001001101
3111012102111010201201
410300311210021031
540433231042331
62203253305501
7240510651232
oct46065441115
914172433651
105114315341
1121949968a3
12ba8935291
136367451c5
1436733b789
151eded7a61
hex130d6424d

5114315341 has 4 divisors (see below), whose sum is σ = 5163968992. Its totient is φ = 5064661692.

The previous prime is 5114315287. The next prime is 5114315363. The reversal of 5114315341 is 1435134115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5114315341 - 211 = 5114313293 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5114315641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24826671 + ... + 24826876.

It is an arithmetic number, because the mean of its divisors is an integer number (1290992248).

Almost surely, 25114315341 is an apocalyptic number.

It is an amenable number.

5114315341 is a deficient number, since it is larger than the sum of its proper divisors (49653651).

5114315341 is a wasteful number, since it uses less digits than its factorization.

5114315341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49653650.

The product of its digits is 3600, while the sum is 28.

The square root of 5114315341 is about 71514.4414856188. The cubic root of 5114315341 is about 1722.9096394221.

Adding to 5114315341 its reverse (1435134115), we get a palindrome (6549449456).

The spelling of 5114315341 in words is "five billion, one hundred fourteen million, three hundred fifteen thousand, three hundred forty-one".

Divisors: 1 103 49653547 5114315341