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5114320222151 = 7898209181737
BaseRepresentation
bin100101001101100010100…
…1111010111011111000111
3200002220221202210010110002
41022123011033113133013
51132243111434102101
614513253011351515
71035332423421350
oct112330517273707
920086852703402
105114320222151
1116a1a754874a8
126a72335b259b
132b1380640c2a
1413976a638d27
158d07dc44d6b
hex4a6c53d77c7

5114320222151 has 8 divisors (see below), whose sum is σ = 5910610851360. Its totient is φ = 4334447956608.

The previous prime is 5114320222129. The next prime is 5114320222169. The reversal of 5114320222151 is 1512220234115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-5114320222151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5114320221151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4104590246 + ... + 4104591491.

It is an arithmetic number, because the mean of its divisors is an integer number (738826356420).

Almost surely, 25114320222151 is an apocalyptic number.

5114320222151 is a deficient number, since it is larger than the sum of its proper divisors (796290629209).

5114320222151 is an equidigital number, since it uses as much as digits as its factorization.

5114320222151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8209181833.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 5114320222151 its reverse (1512220234115), we get a palindrome (6626540456266).

The spelling of 5114320222151 in words is "five trillion, one hundred fourteen billion, three hundred twenty million, two hundred twenty-two thousand, one hundred fifty-one".

Divisors: 1 7 89 623 8209181737 57464272159 730617174593 5114320222151