Base | Representation |
---|---|
bin | 100101001101100011000… |
… | …0001011000101000000111 |
3 | 200002220222200110021112222 |
4 | 1022123012001120220013 |
5 | 1132243123313142043 |
6 | 14513254200402555 |
7 | 1035332643031364 |
oct | 112330601305007 |
9 | 20086880407488 |
10 | 5114333334023 |
11 | 16a1a81922661 |
12 | 6a7237a7645b |
13 | 2b1383282034 |
14 | 13976c28d46b |
15 | 8d07ee84d68 |
hex | 4a6c6058a07 |
5114333334023 has 4 divisors (see below), whose sum is σ = 5114511122808. Its totient is φ = 5114155545240.
The previous prime is 5114333333999. The next prime is 5114333334037. The reversal of 5114333334023 is 3204333334115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5114333334023 - 242 = 716286822919 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5114333334043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88851236 + ... + 88908777.
It is an arithmetic number, because the mean of its divisors is an integer number (1278627780702).
Almost surely, 25114333334023 is an apocalyptic number.
5114333334023 is a deficient number, since it is larger than the sum of its proper divisors (177788785).
5114333334023 is a wasteful number, since it uses less digits than its factorization.
5114333334023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 177788784.
The product of its (nonzero) digits is 116640, while the sum is 35.
Adding to 5114333334023 its reverse (3204333334115), we get a palindrome (8318666668138).
The spelling of 5114333334023 in words is "five trillion, one hundred fourteen billion, three hundred thirty-three million, three hundred thirty-four thousand, twenty-three".
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