Base | Representation |
---|---|
bin | 100101001101100011000… |
… | …0101001100110010100011 |
3 | 200002220222202100002102102 |
4 | 1022123012011030302203 |
5 | 1132243124042142430 |
6 | 14513254234041015 |
7 | 1035332654365166 |
oct | 112330605146243 |
9 | 20086882302372 |
10 | 5114334334115 |
11 | 16a1a82445a86 |
12 | 6a723827916b |
13 | 2b13835422c6 |
14 | 13976c46dadd |
15 | 8d0800d1345 |
hex | 4a6c614cca3 |
5114334334115 has 8 divisors (see below), whose sum is σ = 6148420950480. Its totient is φ = 4083987634272.
The previous prime is 5114334334103. The next prime is 5114334334127.
5114334334115 is nontrivially palindromic in base 10.
It is an interprime number because it is at equal distance from previous prime (5114334334103) and next prime (5114334334127).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5114334334115 - 212 = 5114334330019 is a prime.
It is a super-2 number, since 2×51143343341152 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 934976120 + ... + 934981589.
It is an arithmetic number, because the mean of its divisors is an integer number (768552618810).
Almost surely, 25114334334115 is an apocalyptic number.
5114334334115 is a deficient number, since it is larger than the sum of its proper divisors (1034086616365).
5114334334115 is a wasteful number, since it uses less digits than its factorization.
5114334334115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1869958261.
The product of its digits is 129600, while the sum is 38.
The spelling of 5114334334115 in words is "five trillion, one hundred fourteen billion, three hundred thirty-four million, three hundred thirty-four thousand, one hundred fifteen".
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