Base | Representation |
---|---|
bin | 101111101000111101… |
… | …011110011110010011 |
3 | 11220000221112012021002 |
4 | 233220331132132103 |
5 | 1314230141214341 |
6 | 35255511452215 |
7 | 3460422630533 |
oct | 575075363623 |
9 | 156027465232 |
10 | 51153069971 |
11 | 1a76a635643 |
12 | 9ab708706b |
13 | 4a92912253 |
14 | 26939254c3 |
15 | 14e5c1029b |
hex | be8f5e793 |
51153069971 has 4 divisors (see below), whose sum is σ = 51209221344. Its totient is φ = 51096918600.
The previous prime is 51153069943. The next prime is 51153069991. The reversal of 51153069971 is 17996035115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51153069971 - 26 = 51153069907 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51153069931) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28074320 + ... + 28076141.
It is an arithmetic number, because the mean of its divisors is an integer number (12802305336).
Almost surely, 251153069971 is an apocalyptic number.
51153069971 is a deficient number, since it is larger than the sum of its proper divisors (56151373).
51153069971 is an equidigital number, since it uses as much as digits as its factorization.
51153069971 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56151372.
The product of its (nonzero) digits is 255150, while the sum is 47.
The spelling of 51153069971 in words is "fifty-one billion, one hundred fifty-three million, sixty-nine thousand, nine hundred seventy-one".
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