Base | Representation |
---|---|
bin | 101111101001000001… |
… | …001001111010101001 |
3 | 11220001000100012010122 |
4 | 233221001021322221 |
5 | 1314230413044340 |
6 | 35255544253025 |
7 | 3460434055241 |
oct | 575101117251 |
9 | 156030305118 |
10 | 51154034345 |
11 | 1a770134147 |
12 | 9ab7471175 |
13 | 4a92b8c19b |
14 | 2693ad6b21 |
15 | 14e5d50db5 |
hex | be9049ea9 |
51154034345 has 4 divisors (see below), whose sum is σ = 61384841220. Its totient is φ = 40923227472.
The previous prime is 51154034341. The next prime is 51154034377. The reversal of 51154034345 is 54343045115.
51154034345 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 35816698009 + 15337336336 = 189253^2 + 123844^2 .
It is a cyclic number.
It is not a de Polignac number, because 51154034345 - 22 = 51154034341 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (51154034341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5115403430 + ... + 5115403439.
It is an arithmetic number, because the mean of its divisors is an integer number (15346210305).
Almost surely, 251154034345 is an apocalyptic number.
It is an amenable number.
51154034345 is a deficient number, since it is larger than the sum of its proper divisors (10230806875).
51154034345 is a wasteful number, since it uses less digits than its factorization.
51154034345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10230806874.
The product of its (nonzero) digits is 72000, while the sum is 35.
The spelling of 51154034345 in words is "fifty-one billion, one hundred fifty-four million, thirty-four thousand, three hundred forty-five".
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