Base | Representation |
---|---|
bin | 101111101001000001… |
… | …001001111010100101 |
3 | 11220001000100012010111 |
4 | 233221001021322211 |
5 | 1314230413044331 |
6 | 35255544253021 |
7 | 3460434055234 |
oct | 575101117245 |
9 | 156030305114 |
10 | 51154034341 |
11 | 1a770134143 |
12 | 9ab7471171 |
13 | 4a92b8c197 |
14 | 2693ad6b1b |
15 | 14e5d50db1 |
hex | be9049ea5 |
51154034341 has 2 divisors, whose sum is σ = 51154034342. Its totient is φ = 51154034340.
The previous prime is 51154034339. The next prime is 51154034377. The reversal of 51154034341 is 14343045115.
51154034341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 27269568225 + 23884466116 = 165135^2 + 154546^2 .
It is a cyclic number.
It is not a de Polignac number, because 51154034341 - 21 = 51154034339 is a prime.
Together with 51154034339, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51154034441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25577017170 + 25577017171.
It is an arithmetic number, because the mean of its divisors is an integer number (25577017171).
Almost surely, 251154034341 is an apocalyptic number.
It is an amenable number.
51154034341 is a deficient number, since it is larger than the sum of its proper divisors (1).
51154034341 is an equidigital number, since it uses as much as digits as its factorization.
51154034341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 51154034341 its reverse (14343045115), we get a palindrome (65497079456).
The spelling of 51154034341 in words is "fifty-one billion, one hundred fifty-four million, thirty-four thousand, three hundred forty-one".
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