Base | Representation |
---|---|
bin | 100101001110010101001… |
… | …0010111010100010100111 |
3 | 200010002022221000211120112 |
4 | 1022130222102322202213 |
5 | 1132310100001312413 |
6 | 14514133134323235 |
7 | 1035422431344506 |
oct | 112345222724247 |
9 | 20102287024515 |
10 | 5116015650983 |
11 | 16a2765508256 |
12 | 6a762735951b |
13 | 2b1590979963 |
14 | 13988b89083d |
15 | 8d12c9e42a8 |
hex | 4a72a4ba8a7 |
5116015650983 has 4 divisors (see below), whose sum is σ = 5117419996008. Its totient is φ = 5114611305960.
The previous prime is 5116015650973. The next prime is 5116015651031. The reversal of 5116015650983 is 3890565106115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5116015650983 - 210 = 5116015649959 is a prime.
It is a super-2 number, since 2×51160156509832 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5116015650973) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 702167048 + ... + 702174333.
It is an arithmetic number, because the mean of its divisors is an integer number (1279354999002).
Almost surely, 25116015650983 is an apocalyptic number.
5116015650983 is a deficient number, since it is larger than the sum of its proper divisors (1404345025).
5116015650983 is a wasteful number, since it uses less digits than its factorization.
5116015650983 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1404345024.
The product of its (nonzero) digits is 972000, while the sum is 50.
The spelling of 5116015650983 in words is "five trillion, one hundred sixteen billion, fifteen million, six hundred fifty thousand, nine hundred eighty-three".
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