Base | Representation |
---|---|
bin | 100101001110011000101… |
… | …1111111011010100000111 |
3 | 200010002122100102201201221 |
4 | 1022130301133323110013 |
5 | 1132310321421040120 |
6 | 14514153132501211 |
7 | 1035425426513422 |
oct | 112346137732407 |
9 | 20102570381657 |
10 | 5116136502535 |
11 | 16a2817750873 |
12 | 6a765b91a807 |
13 | 2b15aca11356 |
14 | 13989d94c9b9 |
15 | 8d1384170aa |
hex | 4a7317fb507 |
5116136502535 has 12 divisors (see below), whose sum is σ = 6292756603224. Its totient is φ = 3993082141760.
The previous prime is 5116136502479. The next prime is 5116136502553. The reversal of 5116136502535 is 5352056316115.
It is not a de Polignac number, because 5116136502535 - 215 = 5116136469767 is a prime.
It is a super-2 number, since 2×51161365025352 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5116136502491 and 5116136502500.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 304342369 + ... + 304359178.
It is an arithmetic number, because the mean of its divisors is an integer number (524396383602).
Almost surely, 25116136502535 is an apocalyptic number.
5116136502535 is a deficient number, since it is larger than the sum of its proper divisors (1176620100689).
5116136502535 is an equidigital number, since it uses as much as digits as its factorization.
5116136502535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 608701634 (or 608701593 counting only the distinct ones).
The product of its (nonzero) digits is 405000, while the sum is 43.
The spelling of 5116136502535 in words is "five trillion, one hundred sixteen billion, one hundred thirty-six million, five hundred two thousand, five hundred thirty-five".
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