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51201351241 = 337151932793
BaseRepresentation
bin101111101011110101…
…101001111001001001
311220011022101010201021
4233223311221321021
51314330021214431
635304354352441
73461550206335
oct575365517111
9156138333637
1051201351241
111a794912017
129b0b28b721
134a9c918251
14269a0d27c5
1514ea09ab11
hexbebd69e49

51201351241 has 4 divisors (see below), whose sum is σ = 51353284372. Its totient is φ = 51049418112.

The previous prime is 51201351217. The next prime is 51201351269. The reversal of 51201351241 is 14215310215.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 14215310215 = 52843062043.

It can be written as a sum of positive squares in 2 ways, for example, as 16093459600 + 35107891641 = 126860^2 + 187371^2 .

It is a cyclic number.

It is not a de Polignac number, because 51201351241 - 223 = 51192962633 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51201301241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75966060 + ... + 75966733.

It is an arithmetic number, because the mean of its divisors is an integer number (12838321093).

Almost surely, 251201351241 is an apocalyptic number.

It is an amenable number.

51201351241 is a deficient number, since it is larger than the sum of its proper divisors (151933131).

51201351241 is a wasteful number, since it uses less digits than its factorization.

51201351241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 151933130.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 51201351241 its reverse (14215310215), we get a palindrome (65416661456).

The spelling of 51201351241 in words is "fifty-one billion, two hundred one million, three hundred fifty-one thousand, two hundred forty-one".

Divisors: 1 337 151932793 51201351241