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51202054121 = 67764209763
BaseRepresentation
bin101111101011111000…
…010101011111101001
311220011100200211212212
4233223320111133221
51314330211212441
635304421414505
73461556164501
oct575370253751
9156140624785
1051202054121
111a795252109
129b0b56a435
134a9cb0315a
14269a236a01
1514ea188eeb
hexbebe157e9

51202054121 has 4 divisors (see below), whose sum is σ = 51966263952. Its totient is φ = 50437844292.

The previous prime is 51202054087. The next prime is 51202054147. The reversal of 51202054121 is 12145020215.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51202054121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51202054151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 382104815 + ... + 382104948.

It is an arithmetic number, because the mean of its divisors is an integer number (12991565988).

Almost surely, 251202054121 is an apocalyptic number.

It is an amenable number.

51202054121 is a deficient number, since it is larger than the sum of its proper divisors (764209831).

51202054121 is an equidigital number, since it uses as much as digits as its factorization.

51202054121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 764209830.

The product of its (nonzero) digits is 800, while the sum is 23.

Adding to 51202054121 its reverse (12145020215), we get a palindrome (63347074336).

The spelling of 51202054121 in words is "fifty-one billion, two hundred two million, fifty-four thousand, one hundred twenty-one".

Divisors: 1 67 764209763 51202054121