Base | Representation |
---|---|
bin | 101111101011111000… |
… | …010101100000000011 |
3 | 11220011100200211220211 |
4 | 233223320111200003 |
5 | 1314330211213042 |
6 | 35304421414551 |
7 | 3461556164536 |
oct | 575370254003 |
9 | 156140624824 |
10 | 51202054147 |
11 | 1a795252132 |
12 | 9b0b56a457 |
13 | 4a9cb0317a |
14 | 269a236a1d |
15 | 14ea189017 |
hex | bebe15803 |
51202054147 has 2 divisors, whose sum is σ = 51202054148. Its totient is φ = 51202054146.
The previous prime is 51202054087. The next prime is 51202054151. The reversal of 51202054147 is 74145020215.
51202054147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51202054147 is a prime.
It is not a weakly prime, because it can be changed into another prime (51202054247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25601027073 + 25601027074.
It is an arithmetic number, because the mean of its divisors is an integer number (25601027074).
Almost surely, 251202054147 is an apocalyptic number.
51202054147 is a deficient number, since it is larger than the sum of its proper divisors (1).
51202054147 is an equidigital number, since it uses as much as digits as its factorization.
51202054147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11200, while the sum is 31.
The spelling of 51202054147 in words is "fifty-one billion, two hundred two million, fifty-four thousand, one hundred forty-seven".
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