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51212013 = 317070671
BaseRepresentation
bin1100001101011…
…0111011101101
310120100211200020
43003112323231
5101102241023
65025352353
71161203106
oct303267355
9116324606
1051212013
11269a9386
12151986b9
13a7c0c88
146b313ad
154768de3
hex30d6eed

51212013 has 4 divisors (see below), whose sum is σ = 68282688. Its totient is φ = 34141340.

The previous prime is 51212009. The next prime is 51212027. The reversal of 51212013 is 31021215.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51212013 - 22 = 51212009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 51211983 and 51212001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51210013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8535333 + ... + 8535338.

It is an arithmetic number, because the mean of its divisors is an integer number (17070672).

Almost surely, 251212013 is an apocalyptic number.

It is an amenable number.

51212013 is a deficient number, since it is larger than the sum of its proper divisors (17070675).

51212013 is a wasteful number, since it uses less digits than its factorization.

51212013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17070674.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 51212013 is about 7156.2569126604. The cubic root of 51212013 is about 371.3561457756.

Adding to 51212013 its reverse (31021215), we get a palindrome (82233228).

The spelling of 51212013 in words is "fifty-one million, two hundred twelve thousand, thirteen".

Divisors: 1 3 17070671 51212013