Base | Representation |
---|---|
bin | 111010001110010001101001… |
… | …1110010100100011100110001 |
3 | 2111011022200010022112210201001 |
4 | 1310130203103302210130301 |
5 | 1014111311402111432423 |
6 | 5013115440205042001 |
7 | 212605364651664334 |
oct | 16434432362443461 |
9 | 2434280108483631 |
10 | 512135453624113 |
11 | 139200476255270 |
12 | 49533347256301 |
13 | 18c9c220a820c7 |
14 | 90676b992861b |
15 | 3e31c42340cad |
hex | 1d1c8d3ca4731 |
512135453624113 has 16 divisors (see below), whose sum is σ = 570582020724480. Its totient is φ = 455670412288000.
The previous prime is 512135453624033. The next prime is 512135453624131. The reversal of 512135453624113 is 311426354531215.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-512135453624113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (512135453627113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 196972263 + ... + 199555363.
It is an arithmetic number, because the mean of its divisors is an integer number (35661376295280).
Almost surely, 2512135453624113 is an apocalyptic number.
It is an amenable number.
512135453624113 is a deficient number, since it is larger than the sum of its proper divisors (58446567100367).
512135453624113 is a wasteful number, since it uses less digits than its factorization.
512135453624113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2966648.
The product of its digits is 1296000, while the sum is 46.
The spelling of 512135453624113 in words is "five hundred twelve trillion, one hundred thirty-five billion, four hundred fifty-three million, six hundred twenty-four thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •