Base | Representation |
---|---|
bin | 10111010010110110100101… |
… | …01001011011000101101010 |
3 | 20201101002111012201011111012 |
4 | 23221123102221123011222 |
5 | 23203233420343440224 |
6 | 300540330121503522 |
7 | 13534623015106352 |
oct | 1351332251330552 |
9 | 221332435634435 |
10 | 51225314046314 |
11 | 1535a596379911 |
12 | 58b3986041ba2 |
13 | 22776ac61c4c5 |
14 | c91465aa7b62 |
15 | 5dc74bda380e |
hex | 2e96d2a5b16a |
51225314046314 has 4 divisors (see below), whose sum is σ = 76837971069474. Its totient is φ = 25612657023156.
The previous prime is 51225314046301. The next prime is 51225314046337. The reversal of 51225314046314 is 41364041352215.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 32010531106225 + 19214782940089 = 5657785^2 + 4383467^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12806328511577 + ... + 12806328511580.
Almost surely, 251225314046314 is an apocalyptic number.
51225314046314 is a deficient number, since it is larger than the sum of its proper divisors (25612657023160).
51225314046314 is a wasteful number, since it uses less digits than its factorization.
51225314046314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25612657023159.
The product of its (nonzero) digits is 345600, while the sum is 41.
Adding to 51225314046314 its reverse (41364041352215), we get a palindrome (92589355398529).
The spelling of 51225314046314 in words is "fifty-one trillion, two hundred twenty-five billion, three hundred fourteen million, forty-six thousand, three hundred fourteen".
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