Base | Representation |
---|---|
bin | 10111010011000101010000… |
… | …11010110110111111111111 |
3 | 20201101211211111002111211222 |
4 | 23221202220122312333333 |
5 | 23203401041023114444 |
6 | 300544112145103555 |
7 | 13535322226403633 |
oct | 1351425032667777 |
9 | 221354744074758 |
10 | 51233195519999 |
11 | 15362970251729 |
12 | 58b5405627bbb |
13 | 22783674333bc |
14 | c919b271adc3 |
15 | 5dca5dc89eee |
hex | 2e98a86b6fff |
51233195519999 has 4 divisors (see below), whose sum is σ = 51254392541664. Its totient is φ = 51211998498336.
The previous prime is 51233195519971. The next prime is 51233195520019. The reversal of 51233195519999 is 99991559133215.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51233195519999 - 212 = 51233195515903 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51233195510999) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10598507207 + ... + 10598512040.
It is an arithmetic number, because the mean of its divisors is an integer number (12813598135416).
Almost surely, 251233195519999 is an apocalyptic number.
51233195519999 is a deficient number, since it is larger than the sum of its proper divisors (21197021665).
51233195519999 is a wasteful number, since it uses less digits than its factorization.
51233195519999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21197021664.
The product of its digits is 132860250, while the sum is 71.
The spelling of 51233195519999 in words is "fifty-one trillion, two hundred thirty-three billion, one hundred ninety-five million, five hundred nineteen thousand, nine hundred ninety-nine".
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