Base | Representation |
---|---|
bin | 100101010001110010101… |
… | …1111101010100111011001 |
3 | 200010210112010111221220011 |
4 | 1022203211133222213121 |
5 | 1132420312013102223 |
6 | 14521403034201521 |
7 | 1036104620333443 |
oct | 112434537524731 |
9 | 20123463457804 |
10 | 5123451300313 |
11 | 16a5930766695 |
12 | 6a8b615832a1 |
13 | 2b21a72c6668 |
14 | 139d95211493 |
15 | 8d4156b480d |
hex | 4a8e57ea9d9 |
5123451300313 has 8 divisors (see below), whose sum is σ = 5135715341696. Its totient is φ = 5111187706800.
The previous prime is 5123451300311. The next prime is 5123451300329. The reversal of 5123451300313 is 3130031543215.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5123451300313 - 21 = 5123451300311 is a prime.
It is a super-3 number, since 3×51234513003133 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5123451300311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39454870 + ... + 39584512.
It is an arithmetic number, because the mean of its divisors is an integer number (641964417712).
Almost surely, 25123451300313 is an apocalyptic number.
It is an amenable number.
5123451300313 is a deficient number, since it is larger than the sum of its proper divisors (12264041383).
5123451300313 is a wasteful number, since it uses less digits than its factorization.
5123451300313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 223935.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 5123451300313 its reverse (3130031543215), we get a palindrome (8253482843528).
The spelling of 5123451300313 in words is "five trillion, one hundred twenty-three billion, four hundred fifty-one million, three hundred thousand, three hundred thirteen".
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