Base | Representation |
---|---|
bin | 100101010001110101011… |
… | …0011111111010111001011 |
3 | 200010210202100101111102002 |
4 | 1022203222303333113023 |
5 | 1132421002332424001 |
6 | 14521415542301215 |
7 | 1036110052543415 |
oct | 112435263772713 |
9 | 20123670344362 |
10 | 5123540514251 |
11 | 16a5977060415 |
12 | 6a8b8742780b |
13 | 2b21bc931883 |
14 | 139da2dd59b5 |
15 | 8d41d43846b |
hex | 4a8eacff5cb |
5123540514251 has 4 divisors (see below), whose sum is σ = 5124990713232. Its totient is φ = 5122090315272.
The previous prime is 5123540514221. The next prime is 5123540514263. The reversal of 5123540514251 is 1524150453215.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5123540514251 - 218 = 5123540252107 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5123540514221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 725094191 + ... + 725101256.
It is an arithmetic number, because the mean of its divisors is an integer number (1281247678308).
Almost surely, 25123540514251 is an apocalyptic number.
5123540514251 is a deficient number, since it is larger than the sum of its proper divisors (1450198981).
5123540514251 is a wasteful number, since it uses less digits than its factorization.
5123540514251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1450198980.
The product of its (nonzero) digits is 120000, while the sum is 38.
Adding to 5123540514251 its reverse (1524150453215), we get a palindrome (6647690967466).
The spelling of 5123540514251 in words is "five trillion, one hundred twenty-three billion, five hundred forty million, five hundred fourteen thousand, two hundred fifty-one".
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