Base | Representation |
---|---|
bin | 100101010010000100101… |
… | …1011100011100001010111 |
3 | 200010212002010222120011010 |
4 | 1022210021123203201113 |
5 | 1132423030333434310 |
6 | 14521542532343303 |
7 | 1036125561040566 |
oct | 112441133434127 |
9 | 20125063876133 |
10 | 5124054202455 |
11 | 16a6110016a21 |
12 | 6a90ab474b33 |
13 | 2b227219a1a6 |
14 | 13a011311bdd |
15 | 8d44d5a7320 |
hex | 4a9096e3857 |
5124054202455 has 16 divisors (see below), whose sum is σ = 8198526117600. Its totient is φ = 2732815776768.
The previous prime is 5124054202439. The next prime is 5124054202471. The reversal of 5124054202455 is 5542024504215.
It is an interprime number because it is at equal distance from previous prime (5124054202439) and next prime (5124054202471).
It is not a de Polignac number, because 5124054202455 - 24 = 5124054202439 is a prime.
It is a super-2 number, since 2×51240542024552 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2969871 + ... + 4366719.
It is an arithmetic number, because the mean of its divisors is an integer number (512407882350).
Almost surely, 25124054202455 is an apocalyptic number.
5124054202455 is a deficient number, since it is larger than the sum of its proper divisors (3074471915145).
5124054202455 is a wasteful number, since it uses less digits than its factorization.
5124054202455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1641410.
The product of its (nonzero) digits is 320000, while the sum is 39.
The spelling of 5124054202455 in words is "five trillion, one hundred twenty-four billion, fifty-four million, two hundred two thousand, four hundred fifty-five".
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