51240551000341 has 4 divisors (see below), whose sum is σ = 52893472000384. Its totient is φ = 49587630000300.

The previous prime is 51240551000321. The next prime is 51240551000371. The reversal of 51240551000341 is 14300015504215.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51240551000341 - 2⁷ = 51240551000213 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (31), and also a Moran number because the ratio is a prime number: 1652921000011 = 51240551000341 / (5 + 1 + 2 + 4 + 0 + 5 + 5 + 1 + 0 + 0 + 0 + 3 + 4 + 1).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51240551000311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 826460499975 + ... + 826460500036.

It is an arithmetic number, because the mean of its divisors is an integer number (13223368000096).

Almost surely, 2^{51240551000341} is an apocalyptic number.

It is an amenable number.

51240551000341 is a deficient number, since it is larger than the sum of its proper divisors (1652921000043).

51240551000341 is a wasteful number, since it uses less digits than its factorization.

51240551000341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1652921000042.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 51240551000341 its reverse (14300015504215), we get a palindrome (65540566504556).

The spelling of 51240551000341 in words is "fifty-one trillion, two hundred forty billion, five hundred fifty-one million, three hundred forty-one", and thus it is an aban number.