Base | Representation |
---|---|
bin | 100101010010000110011… |
… | …1111101101101101110101 |
3 | 200010212020022112020212011 |
4 | 1022210030333231231311 |
5 | 1132423141141404140 |
6 | 14521552510324221 |
7 | 1036130215315516 |
oct | 112441477555565 |
9 | 20125208466764 |
10 | 5124114013045 |
11 | 16a6140858565 |
12 | 6a91074b9671 |
13 | 2b22816abb81 |
14 | 13a019240a0d |
15 | 8d45396dcea |
hex | 4a90cfedb75 |
5124114013045 has 8 divisors (see below), whose sum is σ = 6148948980096. Its totient is φ = 4099283100816.
The previous prime is 5124114013021. The next prime is 5124114013097. The reversal of 5124114013045 is 5403104114215.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5124114013045 - 25 = 5124114013013 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5124114012998 and 5124114013016.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4272144 + ... + 5338486.
It is an arithmetic number, because the mean of its divisors is an integer number (768618622512).
Almost surely, 25124114013045 is an apocalyptic number.
It is an amenable number.
5124114013045 is a deficient number, since it is larger than the sum of its proper divisors (1024834967051).
5124114013045 is a wasteful number, since it uses less digits than its factorization.
5124114013045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2027411.
The product of its (nonzero) digits is 9600, while the sum is 31.
The spelling of 5124114013045 in words is "five trillion, one hundred twenty-four billion, one hundred fourteen million, thirteen thousand, forty-five".
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