Base | Representation |
---|---|
bin | 100101010010010000001… |
… | …1100001011001111101011 |
3 | 200010220002001101100122212 |
4 | 1022210200130023033223 |
5 | 1132424323200204011 |
6 | 14522045122435335 |
7 | 1036141256234021 |
oct | 112444034131753 |
9 | 20126061340585 |
10 | 5124440241131 |
11 | 16a6298a16552 |
12 | 6a9198802b4b |
13 | 2b2304160b43 |
14 | 13a04a6c0711 |
15 | 8d47240e08b |
hex | 4a92070b3eb |
5124440241131 has 8 divisors (see below), whose sum is σ = 5436252439344. Its totient is φ = 4813780769280.
The previous prime is 5124440241091. The next prime is 5124440241161. The reversal of 5124440241131 is 1311420444215.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5124440241131 - 210 = 5124440240107 is a prime.
It is a super-2 number, since 2×51244402411312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5124440241161) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 288172430 + ... + 288190211.
It is an arithmetic number, because the mean of its divisors is an integer number (679531554918).
Almost surely, 25124440241131 is an apocalyptic number.
5124440241131 is a deficient number, since it is larger than the sum of its proper divisors (311812198213).
5124440241131 is a wasteful number, since it uses less digits than its factorization.
5124440241131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 576363181.
The product of its (nonzero) digits is 15360, while the sum is 32.
Adding to 5124440241131 its reverse (1311420444215), we get a palindrome (6435860685346).
The spelling of 5124440241131 in words is "five trillion, one hundred twenty-four billion, four hundred forty million, two hundred forty-one thousand, one hundred thirty-one".
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