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5124440241131 = 17523576362641
BaseRepresentation
bin100101010010010000001…
…1100001011001111101011
3200010220002001101100122212
41022210200130023033223
51132424323200204011
614522045122435335
71036141256234021
oct112444034131753
920126061340585
105124440241131
1116a6298a16552
126a9198802b4b
132b2304160b43
1413a04a6c0711
158d47240e08b
hex4a92070b3eb

5124440241131 has 8 divisors (see below), whose sum is σ = 5436252439344. Its totient is φ = 4813780769280.

The previous prime is 5124440241091. The next prime is 5124440241161. The reversal of 5124440241131 is 1311420444215.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5124440241131 - 210 = 5124440240107 is a prime.

It is a super-2 number, since 2×51244402411312 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5124440241161) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 288172430 + ... + 288190211.

It is an arithmetic number, because the mean of its divisors is an integer number (679531554918).

Almost surely, 25124440241131 is an apocalyptic number.

5124440241131 is a deficient number, since it is larger than the sum of its proper divisors (311812198213).

5124440241131 is a wasteful number, since it uses less digits than its factorization.

5124440241131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 576363181.

The product of its (nonzero) digits is 15360, while the sum is 32.

Adding to 5124440241131 its reverse (1311420444215), we get a palindrome (6435860685346).

The spelling of 5124440241131 in words is "five trillion, one hundred twenty-four billion, four hundred forty million, two hundred forty-one thousand, one hundred thirty-one".

Divisors: 1 17 523 8891 576362641 9798164897 301437661243 5124440241131