Base | Representation |
---|---|
bin | 1001100010111110… |
… | …00101100000011111 |
3 | 111020011222010112122 |
4 | 10301133011200133 |
5 | 40444022344103 |
6 | 2204322453155 |
7 | 241002323525 |
oct | 46137054037 |
9 | 14204863478 |
10 | 5125199903 |
11 | 21a00505aa |
12 | bb05041bb |
13 | 638a86585 |
14 | 368972315 |
15 | 1eee37b38 |
hex | 1317c581f |
5125199903 has 4 divisors (see below), whose sum is σ = 5126363088. Its totient is φ = 5124036720.
The previous prime is 5125199887. The next prime is 5125199921. The reversal of 5125199903 is 3099915215.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5125199903 - 24 = 5125199887 is a prime.
It is a super-2 number, since 2×51251999032 = 52535348091422418818, which contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5125199923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 574958 + ... + 583803.
It is an arithmetic number, because the mean of its divisors is an integer number (1281590772).
Almost surely, 25125199903 is an apocalyptic number.
5125199903 is a deficient number, since it is larger than the sum of its proper divisors (1163185).
5125199903 is a wasteful number, since it uses less digits than its factorization.
5125199903 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1163184.
The product of its (nonzero) digits is 109350, while the sum is 44.
The square root of 5125199903 is about 71590.5014858815. The cubic root of 5125199903 is about 1724.1310364518.
The spelling of 5125199903 in words is "five billion, one hundred twenty-five million, one hundred ninety-nine thousand, nine hundred three".
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