Base | Representation |
---|---|
bin | 100101010010101001110… |
… | …1110001100111100111101 |
3 | 200010222022000022100122110 |
4 | 1022211103232030330331 |
5 | 1132433103423322413 |
6 | 14522310335204233 |
7 | 1036201504220511 |
oct | 112452356147475 |
9 | 20128260270573 |
10 | 5125300604733 |
11 | 16a669a636451 |
12 | 6a9398976679 |
13 | 2b241048a32a |
14 | 13a0cca80141 |
15 | 8d4c2c0b8c3 |
hex | 4a953b8cf3d |
5125300604733 has 16 divisors (see below), whose sum is σ = 7193845656000. Its totient is φ = 3236833376640.
The previous prime is 5125300604659. The next prime is 5125300604791. The reversal of 5125300604733 is 3374060035215.
It is not a de Polignac number, because 5125300604733 - 214 = 5125300588349 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5125300604691 and 5125300604700.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5125300604933) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1818048 + ... + 3681833.
It is an arithmetic number, because the mean of its divisors is an integer number (449615353500).
Almost surely, 25125300604733 is an apocalyptic number.
It is an amenable number.
5125300604733 is a deficient number, since it is larger than the sum of its proper divisors (2068545051267).
5125300604733 is a wasteful number, since it uses less digits than its factorization.
5125300604733 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5516252.
The product of its (nonzero) digits is 226800, while the sum is 39.
Adding to 5125300604733 its reverse (3374060035215), we get a palindrome (8499360639948).
The spelling of 5125300604733 in words is "five trillion, one hundred twenty-five billion, three hundred million, six hundred four thousand, seven hundred thirty-three".
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