Base | Representation |
---|---|
bin | 100101010010110000000… |
… | …0110111111100101011101 |
3 | 200010222211111100222112222 |
4 | 1022211200012333211131 |
5 | 1132434020124231143 |
6 | 14522343121435125 |
7 | 1036206606546545 |
oct | 112454006774535 |
9 | 20128744328488 |
10 | 5125508430173 |
11 | 16a679698380a |
12 | 6a943649baa5 |
13 | 2b2444554471 |
14 | 13a10c4dc325 |
15 | 8d4d60ae768 |
hex | 4a9601bf95d |
5125508430173 has 4 divisors (see below), whose sum is σ = 5125651321440. Its totient is φ = 5125365538908.
The previous prime is 5125508430151. The next prime is 5125508430197. The reversal of 5125508430173 is 3710348055215.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5125508430173 - 216 = 5125508364637 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5125508430673) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71391815 + ... + 71463572.
It is an arithmetic number, because the mean of its divisors is an integer number (1281412830360).
Almost surely, 25125508430173 is an apocalyptic number.
It is an amenable number.
5125508430173 is a deficient number, since it is larger than the sum of its proper divisors (142891267).
5125508430173 is a wasteful number, since it uses less digits than its factorization.
5125508430173 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 142891266.
The product of its (nonzero) digits is 504000, while the sum is 44.
The spelling of 5125508430173 in words is "five trillion, one hundred twenty-five billion, five hundred eight million, four hundred thirty thousand, one hundred seventy-three".
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