Base | Representation |
---|---|
bin | 100101010010110100000… |
… | …1000110101010110011111 |
3 | 200011000011212211110100111 |
4 | 1022211220020311112133 |
5 | 1132434304120132041 |
6 | 14522404332510451 |
7 | 1036213133514316 |
oct | 112455010652637 |
9 | 20130155743314 |
10 | 5125643130271 |
11 | 16a6855a15a04 |
12 | 6a947361b427 |
13 | 2b2466427371 |
14 | 13a12236327d |
15 | 8d4e2d1a981 |
hex | 4a96823559f |
5125643130271 has 4 divisors (see below), whose sum is σ = 5125823391600. Its totient is φ = 5125462868944.
The previous prime is 5125643130263. The next prime is 5125643130301. The reversal of 5125643130271 is 1720313465215.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5125643130271 - 23 = 5125643130263 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5125643130071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90088006 + ... + 90144883.
It is an arithmetic number, because the mean of its divisors is an integer number (1281455847900).
Almost surely, 25125643130271 is an apocalyptic number.
5125643130271 is a deficient number, since it is larger than the sum of its proper divisors (180261329).
5125643130271 is a wasteful number, since it uses less digits than its factorization.
5125643130271 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 180261328.
The product of its (nonzero) digits is 151200, while the sum is 40.
Adding to 5125643130271 its reverse (1720313465215), we get a palindrome (6845956595486).
The spelling of 5125643130271 in words is "five trillion, one hundred twenty-five billion, six hundred forty-three million, one hundred thirty thousand, two hundred seventy-one".
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