Base | Representation |
---|---|
bin | 100101010010110100010… |
… | …0111011110000000101101 |
3 | 200011000012102221110121211 |
4 | 1022211220213132000231 |
5 | 1132434313144124013 |
6 | 14522405220554421 |
7 | 1036213262003026 |
oct | 112455047360055 |
9 | 20130172843554 |
10 | 5125651161133 |
11 | 16a685a500688 |
12 | 6a9476252a11 |
13 | 2b2467ca9859 |
14 | 13a123453c4d |
15 | 8d4e38a523d |
hex | 4a9689de02d |
5125651161133 has 16 divisors (see below), whose sum is σ = 5324759283712. Its totient is φ = 4928751504000.
The previous prime is 5125651161089. The next prime is 5125651161173. The reversal of 5125651161133 is 3311611565215.
It is a de Polignac number, because none of the positive numbers 2k-5125651161133 is a prime.
It is a super-2 number, since 2×51256511611332 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5125651161173) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2315713 + ... + 3951433.
It is an arithmetic number, because the mean of its divisors is an integer number (332797455232).
Almost surely, 25125651161133 is an apocalyptic number.
It is an amenable number.
5125651161133 is a deficient number, since it is larger than the sum of its proper divisors (199108122579).
5125651161133 is a wasteful number, since it uses less digits than its factorization.
5125651161133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1636396.
The product of its digits is 81000, while the sum is 40.
The spelling of 5125651161133 in words is "five trillion, one hundred twenty-five billion, six hundred fifty-one million, one hundred sixty-one thousand, one hundred thirty-three".
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