Base | Representation |
---|---|
bin | 101111101111100101… |
… | …111001100111101111 |
3 | 11220022200212210122011 |
4 | 233233211321213233 |
5 | 1314442132031343 |
6 | 35314524302051 |
7 | 3463243421461 |
oct | 575745714757 |
9 | 156280783564 |
10 | 51264330223 |
11 | 1a817418067 |
12 | 9b283a1927 |
13 | 4aac999112 |
14 | 26a4608131 |
15 | 150088b29d |
hex | bef9799ef |
51264330223 has 4 divisors (see below), whose sum is σ = 51431315320. Its totient is φ = 51097345128.
The previous prime is 51264330181. The next prime is 51264330233. The reversal of 51264330223 is 32203346215.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32203346215 = 5 ⋅6440669243.
It is a cyclic number.
It is not a de Polignac number, because 51264330223 - 229 = 50727459311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51264330233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83492088 + ... + 83492701.
It is an arithmetic number, because the mean of its divisors is an integer number (12857828830).
Almost surely, 251264330223 is an apocalyptic number.
51264330223 is a deficient number, since it is larger than the sum of its proper divisors (166985097).
51264330223 is a wasteful number, since it uses less digits than its factorization.
51264330223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 166985096.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 51264330223 its reverse (32203346215), we get a palindrome (83467676438).
The spelling of 51264330223 in words is "fifty-one billion, two hundred sixty-four million, three hundred thirty thousand, two hundred twenty-three".
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