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51300042121 = 103949374439
BaseRepresentation
bin101111110001101110…
…001000010110001001
311220102012002011011001
4233301232020112021
51320030302321441
635322241535001
73464156110006
oct576156102611
9156365064131
1051300042121
111a835599a29
129b38344461
134ab71c0c13
1426a92628ad
151503a92731
hexbf1b88589

51300042121 has 4 divisors (see below), whose sum is σ = 51349417600. Its totient is φ = 51250666644.

The previous prime is 51300042113. The next prime is 51300042133. The reversal of 51300042121 is 12124000315.

51300042121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51300042121 - 23 = 51300042113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51300043121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24686181 + ... + 24688258.

It is an arithmetic number, because the mean of its divisors is an integer number (12837354400).

Almost surely, 251300042121 is an apocalyptic number.

It is an amenable number.

51300042121 is a deficient number, since it is larger than the sum of its proper divisors (49375479).

51300042121 is a wasteful number, since it uses less digits than its factorization.

51300042121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49375478.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 51300042121 its reverse (12124000315), we get a palindrome (63424042436).

The spelling of 51300042121 in words is "fifty-one billion, three hundred million, forty-two thousand, one hundred twenty-one".

Divisors: 1 1039 49374439 51300042121