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51300042113 is a prime number
BaseRepresentation
bin101111110001101110…
…001000010110000001
311220102012002011010202
4233301232020112001
51320030302321423
635322241534545
73464156106665
oct576156102601
9156365064122
1051300042113
111a835599a21
129b38344455
134ab71c0c08
1426a92628a5
151503a92728
hexbf1b88581

51300042113 has 2 divisors, whose sum is σ = 51300042114. Its totient is φ = 51300042112.

The previous prime is 51300042103. The next prime is 51300042133. The reversal of 51300042113 is 31124000315.

It is an a-pointer prime, because the next prime (51300042133) can be obtained adding 51300042113 to its sum of digits (20).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 35950814449 + 15349227664 = 189607^2 + 123892^2 .

It is a cyclic number.

It is not a de Polignac number, because 51300042113 - 24 = 51300042097 is a prime.

It is not a weakly prime, because it can be changed into another prime (51300042103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25650021056 + 25650021057.

It is an arithmetic number, because the mean of its divisors is an integer number (25650021057).

Almost surely, 251300042113 is an apocalyptic number.

It is an amenable number.

51300042113 is a deficient number, since it is larger than the sum of its proper divisors (1).

51300042113 is an equidigital number, since it uses as much as digits as its factorization.

51300042113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360, while the sum is 20.

Adding to 51300042113 its reverse (31124000315), we get a palindrome (82424042428).

The spelling of 51300042113 in words is "fifty-one billion, three hundred million, forty-two thousand, one hundred thirteen".