Base | Representation |
---|---|
bin | 100101010100111111000… |
… | …0000100100011111101001 |
3 | 200011110012210000111200220 |
4 | 1022221332000210133221 |
5 | 1133023331041430441 |
6 | 14524455105320253 |
7 | 1036436512146135 |
oct | 112517600443751 |
9 | 20143183014626 |
10 | 5130305030121 |
11 | 16a88284962a7 |
12 | 6aa354936089 |
13 | 2b2a2a20829b |
14 | 13a4455743c5 |
15 | 8d6b7239466 |
hex | 4aa7e0247e9 |
5130305030121 has 16 divisors (see below), whose sum is σ = 6855169757184. Its totient is φ = 3412827119504.
The previous prime is 5130305030117. The next prime is 5130305030141. The reversal of 5130305030121 is 1210305030315.
It is a cyclic number.
It is not a de Polignac number, because 5130305030121 - 22 = 5130305030117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5130305030091 and 5130305030100.
It is not an unprimeable number, because it can be changed into a prime (5130305030141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3226516 + ... + 4546538.
It is an arithmetic number, because the mean of its divisors is an integer number (428448109824).
Almost surely, 25130305030121 is an apocalyptic number.
It is an amenable number.
5130305030121 is a deficient number, since it is larger than the sum of its proper divisors (1724864727063).
5130305030121 is a wasteful number, since it uses less digits than its factorization.
5130305030121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1322820.
The product of its (nonzero) digits is 1350, while the sum is 24.
The spelling of 5130305030121 in words is "five trillion, one hundred thirty billion, three hundred five million, thirty thousand, one hundred twenty-one".
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