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51304334401 = 479771117279
BaseRepresentation
bin101111110001111110…
…100000010001000001
311220102111011020001101
4233301332200101001
51320032402200101
635322513534401
73464240434645
oct576176402101
9156374136041
1051304334401
111a837a60871
129b39874401
134ab8064828
1426a9a5cc25
15150413e401
hexbf1fa0441

51304334401 has 8 divisors (see below), whose sum is σ = 52449592320. Its totient is φ = 50161313088.

The previous prime is 51304334381. The next prime is 51304334429. The reversal of 51304334401 is 10443340315.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 51304334401 - 217 = 51304203329 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 51304334401.

It is not an unprimeable number, because it can be changed into a prime (51304334491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 512721 + ... + 604558.

It is an arithmetic number, because the mean of its divisors is an integer number (6556199040).

Almost surely, 251304334401 is an apocalyptic number.

It is an amenable number.

51304334401 is a deficient number, since it is larger than the sum of its proper divisors (1145257919).

51304334401 is a wasteful number, since it uses less digits than its factorization.

51304334401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1118303.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 51304334401 its reverse (10443340315), we get a palindrome (61747674716).

The spelling of 51304334401 in words is "fifty-one billion, three hundred four million, three hundred thirty-four thousand, four hundred one".

Divisors: 1 47 977 45919 1117279 52512113 1091581583 51304334401